harga ph suatu larutan tepat jenuh L(OH)3 = 9. ksp senyawa tersebut adalah

pH = 9 --> pOH = 14 - 9 = 5

pOH = 5
[OH-] = 10^-5

tepat jenuh --> Qc = Ksp
L(OH)3 --> L3+             + 3 OH-
               1/3x10^-5            10^-5
Ksp = Qc = [L3+] [OH-]^3
                 = (1/3 x 10^-5) (10^-5)^-3
                 = (1/3 x 10^-20

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