Matematika

Pertanyaan

jika Y = 2t² +2t dan x = 4-3t turunan y terhadap x adalah
jika Y = 2t² +2t dan x = 4-3t turunan y terhadap x adalah

2 Jawaban

  • y = 2t² + 2t
    dy/dt = 4t + 2

    x = 4 - 3t
    3t = 4 - x
    t  = 4/3 - 1/3 x
    dt/dx = -1/3

    y' = dy/dx

    dy/dx = dy/dt . dt/dx
    dy/dx = (4t +2)(-1/3)
    y' = - 1/3 (4t +2)  dengan t = 4/3 - 1/3 x

    y' = -1/3 { 4 (4/3 - 1/3 x) + 2}
    y' = -1/3 {16/3 - 4/3 x + 2)
    y' = - 1/3 (1/3) (16 - 4x + 6)
    y' = -1/9 ( 22- 4x)
    y' = (4x -22)/(9)
  • x = 4 - 3t => 3t = 4 - x => t = (4 - x)/3
    y = 2t^2 + 2t
    y = 2((4 - x)/3)^2 + 2(4 - x)/3
    y = 2(16 - 8x + x^2)/9 + (8 - 2x)/3
    y = 2(16 - 8x + x^2)/9 + 3(8 - 2x)/9
    y = (32 - 16x + 2x^2 + 24 - 6x)/9
    y = (2x^2 - 22x + 56)/9
    y = 2/9 x^2 - 22/9 x + 56/9
    dy/dx = 4/9 x - 22/9
    dy/dx = (4x - 22)/9