tentukan persamaan garis singgung kurva y=x2(x-3) yang tegak lurua garis 4x-24y-1=0

4x - 24y - 1 = 0 --> m = 4/24 = 1/6
tegak lurus m = -1 / (1/6) = -6
y = x²(x - 3)
y = x³ - 3x²
turunan = 0
3x² - 6x = 0
3x(x - 2) = 0
x = 0 dan x = 2
x = 0
y = (0)³ - 3(0)² = 0
(x1,y1) = (0,0)
y - y1 = m(x - x1)
y - 0 = -6(x - 0)
y = -6x
dan
x = 2
y = (2)³ - 3(2)² = 8 - 12 = -4
(x1,y1) = (2,-4)
y - (-4) = -6(x - 2)
y + 4 = -6x + 12
y + 6x = 8