Integral(x+1) (x kuadrat + 2x - 8)pangkat 4 dx

misal x² + 2x - 8 = u
(2x + 2)dx = du
2(x+1)dx = du
(x+1)dx = du/2

(x+1)(x²+2x-8)^4 dx
(x²+2x-8)^4 (x+1)dx
ganti dengan u
u^4 du/2
(1/2) u^4 du
baru integralkan
(1/2)(1/(4+1)) u^(4+1) + C
(1/2)(1/5) u^5 + C
(1/10) u^5 + C
kembalikan u ke awal
(1/10)(x² + 2x - 8)^5 + C