nomer 3 ajah tolong dibantu ya
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Pertanyaan
nomer 3 ajah tolong dibantu ya
1 Jawaban
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1. Jawaban Arifuluka
2.
Mr = 56
Massa = Mr x mol = 56 x 1 = 56 gram
3.
Mr = 2 x 56 + 3 x 32 + 12 x 16 = 400
Mol = Massa ÷ Mr = 20 ÷ 400 = 0,05 mol
4.
Mr = 12 x 12 + 22 x 1 + 11 x 16 = 342
Mol = 17,1 ÷ 342 = 0,05 mol
5.
Mr = 2 x 35,5 = 71
6.
Mr = 1 x 12 + 1 x 16 + 2 x 14 + 4 x 1 = 60
Massa = 60 x 2 = 120 gram
7.
Mr = 2 x 14 + 8 x 1 + 1 x 32 +4 x 16 = 132
Mol = 1,35 ÷ 132 = 0,01
8.
Massa = 58,5 x 0,2 = 11,7 gram
9.
Mr = 1 x 23 + 1 x 14 + 3 x 16 = 85
Massa = 85 x 0,25 = 21,25 gram
10.
Mr = 2 x 1 + 1 x 32 + 4 x 16 = 98
Mol = 4,6 ÷ 98 = 0,04