Bila f(x)=x^2(2x+3)^3. Maka turunan pertama f(x)adalah f'(x).....

u = x^2
u' = 2x

v = (2x+3)^3
v' = 3(2x+3)^2

f'(x) = u'v + uv'
f'(x) = 2x(2x+3)^3 + (x^2)(3(2x+3)^2
f'(x) = 2x(2x+3)^3 + 3x^2(2x+3)^2