tolong. di bantu

[tex] 3x^{2} + 2x - 5 = 0 \\ 3x^{2} + 5x - 3x - 5 = 0 \\ x(3x + 5) - 1 (3x + 5) = 0 \\ (x - 1)(3x + 5) = 0 \\ x - 1 = 0 \\ x_1= 1 \\ \\ \\ 3x + 5 = 0 \\ x_2 = - \dfrac{5}{3} \\ \\ \\ \\ \dfrac{1}{x_{1}} + \dfrac{1}{x_{2}} \\ = \dfrac{1}{1} + \dfrac{1}{ - \dfrac{ 5}{3}} \\ = 1 - \dfrac{3}{5} \\ = \dfrac{2}{5} [/tex]