please bantui soal iini beserta cara jalannya

suku banyak

f(-1)= -2
f(3)= 7

g(-1)= 3
g(3)= 2

h(x) = f(x). g(x)
dibagi x² -2x -3 --> s(x) = ax + b
s(x) = h(x) = f(x). g(x)
s(-1) = f(-1) g(-1) --> a + b = (-2)(3)
- a + b = - 6....(1)

s(3) = f(3) g(3) ---> 3a + b = (7)(2)
3a + b = 14 ...(2)
.
- a + b = - 6
3a + b = 14
...............(-)
-4a  = -20
a = 5
b = - 6 + a  --> b = - 1
..
s(x)= ax + b
s(x)=5x - 1