diketahui AB = 9 cm, BC = 12 cm, AE = 20 cm. keliling segitiga ACG adalah...

AB = 9 cm
BC = 12 cm
AE = CG = 20 cm

AC = √(AB² + BC²)
AC = √(9² + 12²)
AC = √(81 + 144)
AC = √225
AC = 15 cm

AG = √(AC² + CG²)
AG = √(15² + 20²)
AG = √(225 + 400)
AG = √625
AG = 25 cm

Keliling segitiga ACG
= AC + CG + AG
= 15 + 20 + 25
= 35 + 25
= 60 cm (Opsi A)


Semoga bermanfaat #salammath