integral sin (2x-3) dx..??
Matematika
ridwansmatrik
Pertanyaan
integral sin (2x-3) dx..??
1 Jawaban
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1. Jawaban NellaPutriS
u = 2x - 3
du = 2 dx
( 1 / 2 ) du = dx
( 1 / 2 ) * int [ sin u du ]
= ( 1 / 2 ) * ( - cos u ) + C
= ( - 1 / 2 ) cos u + C
= ( - 1 / 2 ) cos ( 2x - 3 ) + C