itegral pangkat 2 -1 (x pangkat 2 + x - 2) dx

int [-1 s.d 2] (x² + x - 2) dx
= (1/3)x³ + (1/2)x² - 2x [-1 s.d 2]
= [(1/3)(8) + (1/2)(4) - 4] - [(1/3)(-1) + (1/2)(1) + 2]
= (8/3 + 2 - 4) - (-1/3 + 1/2 + 2)
= 8/3 - 2 + 1/3 - 1/2 - 2
= 3 - 4 - 1/2
= 7 - 1/2
= 13/2