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Matematika
WildanReza
Pertanyaan
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1 Jawaban
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1. Jawaban IvonePP
BO = √(BC²-CO²)
= √(20²-12²)
= √(400-144)
= √(256)
= 16cm
DO ➡ L = ½.d1.d2
300 = ½(DO+OB)24
300 = (DO+16)12
300:12 = DO+16
25 = DO+16
DO = 25-16
DO = 9cm
BC=BA=20cm
AD=DC=?
AC=AO+OC ➡ OC = AC÷2
AD = √(DO²+OC²)
= √(9²+12²)
= √(81+144)
= √(225)
AD = 15cm
AD=DC=15cm
Keliling = AD+DC+BC+BA
= 15+15+20+20
= 70cm
Keliling = 70cm
AD = 15cm