Jika g(x) = (x - 1)²√1 + 2x maka g'(x)=

dianggap dlm satu akar pngkat dua
u = (x - 1)² ─> u' = 2(x - 1)
v = √(1 + 2x) ──> v' = (1/2)(1 + 2x)^-(1/2) = 1/(2√(1 + 2x))
g'(x) = u'v + v'u = 2(x - 1)√(1 + 2x) + [1/√(1 + 2x)](x - 1)²
= (x - 1)(5x + 1)/√(1 + 2x)