Hitung volume 0,8 gram gas SO3 pada keadaan : (P, T) sama diketahui 1 liter gas CO2=2,2 gram.

mol SO3 = 0.8/80 = 0.01
mol CO2 = 2.2/44 = 0.05

V1 : n1 = V2 : n2
V1 : 0.01 = 1 : 0.05
V1 = 0.2 L

Mr CO2 = (12 + 16 + 16) = 44 g/mol
mol CO2 = 2.2 / 44 = 0.05 mol
0,05 mol gas volumenya 1 L

Volume 1 mol gas = 1/0.05 × 1 = 20 L

Mr SO3 = (32 + 3 × 16) = 80 gram/mol
mol SO3 = 0.8/80 = 0.01 mol

V SO3 = 0.01 × 20 = 0.2 L