100ml larutan NH4OH 0,1 M ( kb = 10-5 ) ditambah 100ml larutan NH4CI 0,1 M , maka pH yang didapat adalah

Mol NH4OH = 100 ml * 0,1 M = 10 mmol
Mol NH4Cl = 100 ml * 0,1 M = 10 mmol
Kb = 10^-5
NH4OH -> basa
NH4Cl -> as.konj(garamnya)
BUFFER
OH- = 10^-5 * 10
OH- = 10^-6
pOH = 6
pH = 14 -6 =8