nilai mutlak 2 | × | - | × - 1| + 3 | × + 1 | > 1 please help me
Matematika
sitimamluatun
Pertanyaan
nilai mutlak
2 | × | - | × - 1| + 3 | × + 1 | > 1
please help me
2 | × | - | × - 1| + 3 | × + 1 | > 1
please help me
2 Jawaban
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1. Jawaban dewaayusriastari
2x + x + 1 + 3x + 3 > 1
6x > -3
x > -3/6
x > -1/2
tolong dibantu koreksi apabila salah -
2. Jawaban Achilies
| × | - | × - 1| + 3 | × + 1 | > 1
x-|x-1| + 3|x+1| >1
3|x+1| - |x-1| >1-x
(3|x+1| - |x-1|)² >(1-x)²
9x²+18x+9 - x²-2x-1 >(1-x)²
8x²+16x+8 > 1²-x²-2x
8x²+16x+8 - 1² + x² + 2x >0
8x²+16x+8 - 1 + x² + 2x >0
9x² + 18x - 7 > 0
(3x+7)(3x-1) >0
batas x=-7/3
x=1/3