diketahui sudut A=68 panjang a=10 cm. panjang b=8cm. besar sudut c ?

a/sin A = b/sin B
sin B = 8 sin 68/ 10
sinB = 7,42/10
<B = 47,88°

<C = 180 - (68+47,88) = 64,12°

a/sinA = c/sinC
c = 8 sin 64,12/sin 68
c = 7,2/sin 68
c = 6,67cm