tentukan nilai stasioner dari f(x)=x pangkat 3 -12x+10?

f(x) = x³-12x +10
f'(x) = 3x² -12
0 = 3x²-12
0 = x²-4
x = ±2

saat x = 2
f(2) = 2³-12*2 +10 = -6

saat x = -2
f(-2) = -2³ -12*-2 +10 = 26