Matematika

Pertanyaan

tentukan hasil penjumlahan berikut :
A) 5
∑ 4-2k
k=1
B) 10
∑ 1/k+2
k=1
C) 6
∑ k+(k+1)(k+2)
k=1

1 Jawaban

  • Sigma

    a.
    5
    ∑  4- 2k
    k = 1
    .
    k =1 --> a = 4-2 = 2
    b= -2
    s5 = 5/2 (2a - 4b)
    s5 = 5/2 (4 -8)
    s5 = 5/2 (-4) = -10

    b.
    k = 1 --> a = 1/1 +2  = 3
    k = 2 --> u2 = 1/2 + 2 = 2 1/2
    k = 3 --> u3 = 1/3 + 2 = 2 1/3
    ...
    2 + 2 1/2 +...+ 2 1/10
    2(10) + (1/2 + 1/3 +...1/10)
    20 + (2)
     = 22

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