Matematika

Pertanyaan

tentukan HP dari
log (1/81)^(10+3x-x²) = 1
tentukan HP dari log (1/81)^(10+3x-x²) = 1

1 Jawaban

  • log(1/81)^(10+3x-x²) = 1
    log(3^(-4))^(10+3x-x²) = 1
    log 3^(-40-12x+4x²) = 1
    (-40-12x+4x²) . log3 = 1
    (4x²-12x-40) = 1/log3
    (2x+10)(2x-4) = 1/log3

    didapatkan:
    2x+10 = 1/log3
    2x = 1/log3 -10
    x = (1-10log3)/(2log3)
    atau
    2x-4 = 1/log3
    2x = 1/log3 +4
    x = (1+4log3)/(2log3)