tentukan HP dari log (1/81)^(10+3x-x²) = 1
Matematika
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Pertanyaan
tentukan HP dari
log (1/81)^(10+3x-x²) = 1
log (1/81)^(10+3x-x²) = 1
1 Jawaban
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1. Jawaban kircyber
log(1/81)^(10+3x-x²) = 1
log(3^(-4))^(10+3x-x²) = 1
log 3^(-40-12x+4x²) = 1
(-40-12x+4x²) . log3 = 1
(4x²-12x-40) = 1/log3
(2x+10)(2x-4) = 1/log3
didapatkan:
2x+10 = 1/log3
2x = 1/log3 -10
x = (1-10log3)/(2log3)
atau
2x-4 = 1/log3
2x = 1/log3 +4
x = (1+4log3)/(2log3)