jika f(x)= (3x2 - 5x) dibagi (x-3),maka f'(x)

u = 3x² - 5x ──> u' = 6x - 5
v = (x - 3) ──> v' = 1
f'(x) = (u'v - v'u)/v²
= ((6x - 5)(x - 3) - 1(3x² - 5x))/(x - 3)²
= 3(x² - 6x + 5)/(x - 3)²