jika 3logx + log 6x - log2x - log 24=0 maka nilai x..

Bab Logaritma

³log x + log 6x - log 2x - log 24 = 0
³log x + log (6x/2x) - log 24 = 0
³log x + log (3/24) = 0
³log x + log 1/8 = 0
³log x + log [tex] 2^{-3} [/tex] = 0
³log x - 3 . log 2 = 0
³log x = 3 . log 2
[tex] 3^{ ^{3}log x } [/tex] = [tex] 3^{ 3 . log 2 } [/tex]
x = [tex](3^3)^{log 2}[/tex]
x = [tex]9^{log 2}[/tex]