tolong dikerjakan menggunakan cara,nanti yang jawaban nya benar,aku jadiin jawaban terbaik

sisi persegi = 40 ÷ 4 = 10 cm

s² = a² + t²
s² = 5² + 12²
s² = 25 + 144
s² = 169
s = √169
s = 13 cm

Luas limas :
= Luas alas + Jumlah luas sisi tegak
= (s × s) + (½ × a × t × 4)
= (10 × 10) + (½ × 10 × 13 × 4)
= 100 + 260
= 360 cm² [A]

sisi alas = K/4
= 40/4
= 10 cm
t segitiga = akar [(T limas)^2 + (1/2×s)^2]
= akar [ 12^2 + (1/2×10)^2 ]
= akar [ 12^2 + 5^2 ]
= akar [ 144 + 25 ]
= akar 169
= 13 cm
L permukaan limas = (s×s) + (4×1/2×s×t)
= (10×10) + (4×1/2×10×13)
= 100 + 260
= 360 cm^2