Fungsi f : R->R dngan g : R->R dirumuskan dengan f(x)=1/2x - 1 dan g(x)=2x + 4. Tentukan (gof)-1(6)
Matematika
Sesi07
Pertanyaan
Fungsi f : R->R dngan g : R->R dirumuskan dengan f(x)=1/2x - 1 dan g(x)=2x + 4. Tentukan (gof)-1(6)
2 Jawaban
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1. Jawaban Faldibru
(gof)(x)=g(f(x))
=g(1/2x-1)
=2(1/2x-1)+4
=x-2+4
=x+2
(gof)-1(x)=y-2
ykni
y=x+2
x=y-2
(gof)-1(y)=y-2
(gof)-1(x)=x-2
jadi, (gof)-1(6)=6-2
=4 -
2. Jawaban FYANANDA
(gof)(x)=g(f(x))
=g(1/2x-1)
=2(1/2x-1)+4
=x-2+4
=x+2
(gof)-1(x)=y-2
ykni
y=x+2
x=y-2
(gof)-1(y)=y-2
(gof)-1(x)=x-2
jadi, (gof)-1(6)=6-2
=4