Soal integral di bantu gan

[tex] \int\limits^1_{1/2} {\frac{1}{x^3}} \, dx [/tex]
[tex] =\int\limits^1_{1/2} {x^{-3}} \, dx [/tex]
[tex]= - \frac{1}{2} {x^{-2}} [/tex]
[tex]=- \frac{1}{2x^2} [/tex]
[tex]=- \frac{1}{2(1)^2} -(- \frac{1}{2(1/2)^2} )[/tex]
[tex]=- \frac{1}{2} -(- \frac{1}{2(1/4)} )[/tex]
[tex]=- \frac{1}{2} + \frac{1}{1/2} [/tex]
[tex]=- \frac{1}{2} + 2 [/tex]
[tex]= \frac{3}{2} [/tex]