jika vektor a=(3,1,2) b=(-4,3,5) c=(3,-2-2), maka vektor a-2b+3c=

(3,1,2)-[2(-4,3,5)]+[3(3,-2,-2)]
(3,1,2)-(-8,6,10)+(9,-6,-6)
[(3-(-8)+9),(1-6-6),(2-10-6)]
(20,-11,-14) itulah jawabannya

diketahui:
a = (3i+j+2k)
b = ((-4)i+3j+5k)
c = (3i-2j-2k)

ditanya:
a-2b+3c =?

jawab:
a-2b+3c
=(3i+j+2k)-(2×((-4)i+3j+5k)+(3(3i-2j-2k)
=(3i+j+2k)-((-8)i+6j+10k)+(9i-6j-6j)
=(20i-11j-14k)

jadi vektor a-2b+3c = 20i-11j-14k