Matematika

Pertanyaan

(-7a²)² =
(-4p³q³r)³ =
(x+y)² =
(3x+4)² =
(5x-7)² =
(x+....)² = ...... + ..... + ....
(4y-...)² = .... - 40y + ....
(5p - 2q)³ = .....
(3x+y)⁴ = ....

Saya mohon jawabannya .!!!
Terima kasih sebelumnya .

2 Jawaban

  • 49a⁴
    -64p⁹q⁹r³
    x²+2xy+y²
    9x²+24x+16
    25x²-70x+49
    itu yg (x+..)² nggk mudeng
    yg (4y-...)² juga nggk mudeng
    1 x 125p³+ 3 x 25p² x -2q + 3 x 5p x 4q² + 1 x 8q³ = 125p³ - 150p²q + 60pq² + 8q³
    1 x 81x⁴ + 4 x  27x³ x y + 6 x 9x² x y² + 4 x 3x x y³ + 1 x y⁴ = 81x⁴+108x³y+54x²y²+12xy³+y⁴

    #NB: dua nomor terakhir itu pake segitiga pascal.
  • 1. (-7a^{2} )^2 =(-7 a^{2}) . (-7 a^{2}) = 49 a^{4}
    2. (x+y)^{2} = (x+y) . (x+y) = x^{2} + xy + xy+ y^{2} = x^{2} +2xy + y^{2}
    3. (3x+4)^{2} = (3x+4) . (3x+4) = 9x^{2} + 24x +16
    4. (5x-7)^{2} = (5x-7) . (5x-7) = 25x^{2} -70x + 49

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