tolong cariin dong teman pakai jalan nya ya

Aturan cosinus

AB = 2√2
BC = 2
sin θ = 1/3 --> cos θ = √(1- sin²θ) = √(8/9) =2/3 √2

AC² = AB²+BC² - 2 AB.BC cos θ
AC² = 8 + 4 - 8√2 (2/3 √2)
AC² = 12 - 32/3 = 4/3
AC = ²/₃ √3