sin 120 + sec 150 . tan 225 --------------------------------------- sin 270 + cos 330

½√3 + (-⅔√3) . 1
= -------------------------
-1 + ½√3

½√3 - ⅔√3 -1 - ½√3
= ----------------- X -------------
-1 + ½√3 -1 - ½√3

-¹/6 √3 (-1 - ½√3)
= ------------------------
1 - ¾

¹/6 √3 + ¼
= ----------------- = 4(¹/6 √3 + ¼) = ⅔√3+1
¼

Maaf kalo salah

(sin 120 + sec 150 . tan 225)/(sin 270 + cos 330)
= (1/2√3 + (-2/3√3) . 1)/(-1 + 1/2√3)
= (1/2√3 - 2/3√3)/(-1 + 1/2√3)
= √3(1/2 - 2/3)/(-1 + 1/2√3)
= √3(-1/6)/(-1 + 1/2√3)
= (-1/6√3)/(-1 + 1/2√3)